Stoichiometry Worksheet PDF Details

The Stoichiometry Worksheet form serves as an essential tool for students and professionals dealing with chemical equations, facilitating a deeper understanding of the stoichiometric relationships between reactants and products in chemical reactions. This document, consisting of a series of targeted questions and a key for correct answers, guides users through the process of calculating the moles and grams of substances involved in various chemical reactions. Through questions that range from the decomposition of potassium chlorate (KClO3) to the combustion of butane (C4H10), learners can explore how different quantities of reactants lead to specific amounts of products, drawing connections between theoretical calculations and practical applications. This form not only includes straightforward calculations, such as determining how many grams of oxygen (O2) are produced from a given amount of potassium chlorate, but also challenges users with more complex scenarios, like the amount of water (H2O) produced from the reaction of oxygen. Whether for educational purposes or practical applications in a laboratory setting, the Stoichiometry Worksheet form is a valuable resource for mastering the principles of stoichiometry, featuring a wide array of exercises that cover key concepts and calculation strategies.

QuestionAnswer
Form NameStoichiometry Worksheet
Form Length4 pages
Fillable?No
Fillable fields0
Avg. time to fill out1 min
Other namesFe203, beginning stoichiometry worksheet, stoichiometry worksheet, stoichiometry worksheet na2sio3

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Stoichiometry Worksheet and Key

2 KClO3 è 2 KCl + 3 O2

1. How many moles of O2 will be formed from 1.65 moles of KClO3?

1.65 mol KClO3

mol O2

mol O2

 

=

 

mol KClO3

 

2. How many moles of KClO3 are needed to make 3.50 moles of KCl?

3.50mol KCl

= mol KClO3

3. How many moles of KCl will be formed from 2.73 moles of KClO3?

=

4 Fe + 3 O2 è 2 Fe2O3

4. How many moles of Fe2O3 are produced when 0.275 moles of Fe is reacted?

0.275 mol Fe

= mol Fe2O3

5. How many moles of Fe2O3 are produced when 31.0 moles of O2 is reacted?

=

6. How many moles of O2 are needed to react with 8.9 moles of Fe?

=

2H2O è 2 H2 + O2

7.How many moles of O2 are produced when 1.26 moles of H2O is reacted?

8.How many moles of H2O are needed to produce 55.7 moles of H2?

9.If enough H2O is reacted to produce 3.40 moles of H2, then how may moles of O2 must have been made? (a bit challenging, but just think about it and you can probably figure it out)

2 KClO3 è 2 KCl + 3 O2

10. How many grams of O2 will be formed from 3.76 grams of KClO3?

 

3.76g KClO3 1 mol KClO3

mol O2

g O2 =

g O2

122.55 g KClO3

mol KClO3

mol O2

 

11. How many grams of KClO3 are needed to make 30.0 grams of KCl?

30.0 g KCl

mol KCl

mol KClO3

g KClO3

=

 

g KCl

mol KCl

mol KClO3

 

 

12.How many grams of KCl will be formed from 2.73 g of KClO3?

2.73g KClO3

=

4 Fe + 3 O2 è 2 Fe2O3

13. How many grams of Fe2O3 are produced when 42.7 grams of Fe is reacted?

42.7 g Fe

mol Fe

mol Fe2O3

g Fe2O3

 

g Fe

mol Fe

=

 

mol Fe2O3

14. How many grams of Fe2O3 are produced when 17.0 grams of O2 is reacted?

17.0 g O2

=

 

15. How many grams of O2 are needed to react with 125 grams of Fe?

=

Some cars can use butane (C4H10) as fuel:

 

2 C4H10 + 13 O2 è 8 CO2 + 10 H2O

 

16.

How many grams of CO2 are produced from the combustion of 100. grams of butane?

100. g C4H10

=

 

 

17.

How many grams of O2 are needed to react with of 100. grams of butane?

 

100. g C4H10

=

 

 

18 How many grams of H2O are produced when 5.38g of O2 is reacted?

 

g KClO3

g KCl

g Fe2O3

g Fe2O3

g CO2

g O2

2 KCl + 3 O2
2 KClO3

KEY

è

1. How many moles of O2 will be formed from 1.65 moles of KClO3?

1.65 mol KClO3

3 mol O2

2.48 mol O2

 

=

 

2 mol KClO3

 

2. How many moles of KClO3 are needed to make 3.50 moles of KCl?

3.50 mol KCl

2 mol KClO3

mol KClO3

 

= 3.50

 

2 mol KCl

 

3. How many moles of KCl will be formed from 2.73 moles of KClO3?

2.73 moles KClO3

2 mol KCl

2.73 mol KCl

 

=

 

2 mol KClO3

 

 

4 Fe + 3 O2 è 2 Fe2O3

4. How many moles of Fe2O3 are produced when 0.275 moles of Fe are reacted?

0.275 mol Fe

2 mol Fe2O3

=

0.138 mol Fe2O3

 

4 mol Fe

 

 

 

5. How many moles of Fe2O3 are produced when 31.0 moles of O2 are reacted?

31.0 mol O2

2 mol Fe2O3

= 20.7 mol Fe2O3

 

3 mol O2

 

 

6. How many moles of O2 are needed to react with 8.9 moles of Fe?

8.9 mol Fe

3 mol O2

=

6.7

mol O2

 

4 mol Fe

 

 

 

 

2H2O è 2 H2 + O2

7.How many moles of O2 are produced when 1.26 moles of H2O is reacted?

1.26mol H2O 1 mol O2= .630 mol O2 2 mol H2O

8.How many moles of H2O are needed to produce 55.7 moles of H2?

55.7mol H2 2 mol H2O = 55.7 mol H2O 2 mol H2

9.If enough H2O is reacted to produce 3.40 moles of H2, then how may moles of O2 must have been made? (a bit challenging, but just think about it and you can probably figure it out)

3.40 mol H2 1 mol O2

1.70

mol O2

=

2 mol H2

 

 

2 KClO3 è 2 KCl + 3 O2

10. How many grams of O2 will be formed from 3.76 grams of KClO3?

 

 

3.76g KClO3

1 mol KClO3

3

mol O2

32.00 g O2

=

1.47 g O2

 

122.55 g KClO3

2 mol KClO3

1 mol O2

 

 

11. How many grams of KClO3 are needed to make 30.0 grams of KCl?

 

 

30.0 g KCl

1 mol KCl

2

mol KClO3

122.55 g KClO3

= 49.3 g KClO3

 

74.55 g KCl

2

mol KCl

1 mol KClO3

 

12. How many grams of KCl will be formed from 2.73 g of KClO3?

2.73 g KClO3 1 mol KCl O3

2

mol KCl

74.55 g

= 1.66 g KCl

122.55 g KClO3

2

mol KCl O3

1 mol KCl

4 Fe + 3 O2 è 2 Fe2O3

13. How many grams of Fe2O3 are produced when 42.7 grams of Fe is reacted?

42.7 g Fe

1

mole Fe

2

mol Fe2O3

159.70 g Fe2O3

=

61.0 g Fe2O3

 

55.85

g Fe

4

mol Fe

1 mol Fe2O3

 

 

 

14. How many grams of Fe2O3 are produced when 17.0 grams of O2 is reacted?

=

56.6 g Fe2O3

17.0 g O2

1 mol O2

2 mol Fe2O3

159.70

g Fe2O3

 

 

 

 

 

 

 

 

 

32.00

g O2

3

mol O2

1 mol Fe2O3

 

 

15. How many grams of O2 are needed to react with 125 grams of Fe?

125 g Fe

1 mol Fe

3 mol O2

32.00 g O2

=

53.7

g O2

 

55.85

g Fe

4

mol Fe

1 mol O2

 

 

g

 

 

 

 

 

 

Some cars can use butane (C4H10) as fuel:

 

 

 

 

 

 

 

 

2 C4H10 + 13 O2 è 8 CO2 + 10 H2O

 

 

 

16. How many grams of CO2 are produced from the combustion of 100. grams of butane?

 

100. g C4H10

1 mol C4H10

8 mol CO2

44.01 g CO2

=

303

g CO2

 

58.14 g C4H10

2 mol C4H10

1 mol CO2

 

 

 

 

17. How many grams of O2 are needed to react with of 100. grams of butane?

100. g C4H10

1 mol C4H10

13 mol O2

32.00 g O2

=

358

g O2

 

58.14 g C4H10

2 mol C4H10

1 mol O2

 

 

 

 

18 How many grams of H2O are produced when 5.38g of O2 is reacted?

 

 

 

5.38g O2

1 mol O2

10 mol H2O

18.02 g H2O

=

2.33

g H2O

 

32.00 g O2

13 mol O2

1 mol H2O

 

 

 

 

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